The bond order of O_2^+ is the same as in | vedclass

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(A) The total number of electrons in $O_2^+$ is $15$. The molecular orbital configuration is $KK(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_z)^2(\pi 2p_x)^

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$N_2^+$

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(A) The total number of electrons in $O_2^+$ is $15$. The molecular orbital configuration is $KK(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_z)^2(\pi 2p_x)^2(\pi 2p_y)^2(\pi^* 2p_x)^1$. Bond order $= \frac{1}{2}(N_b - N_a) = \frac{1}{2}(10 - 5) = 2.5$. The total number of electrons in $N_2^+$ is $13$. The molecular orbital configuration is $KK(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_z)^2(\pi 2p_x)^2(\pi 2p_y)^1$. Bond order $= \frac{1}{2}(9 - 4) = 2.5$. Thus,the bond order of $O_2^+$ is the same as that of $N_2^+$.

The bond order of $O_2^+$ is the same as in

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