The total number of species from the followin | vedclass

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(C) To determine the number of unpaired electrons,we use Molecular Orbital Theory $(MOT)$: $N_2$: $(14 \ e^-) \rightarrow \sigma 1s^2, \sigma^* 1s^2,

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(C) To determine the number of unpaired electrons,we use Molecular Orbital Theory $(MOT)$: $N_2$: $(14 \ e^-) \rightarrow \sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2 = \pi 2p_y^2, \sigma 2p_z^2$ ($0$ unpaired $e^-$) $O_2$: $(16 \ e^-) \rightarrow \dots, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1 = \pi^* 2p_y^1$ ($2$ unpaired $e^-$) $C_2^{-}$: $(13 \ e^-) \rightarrow \dots, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^1$ ($1$ unpaired $e^-$) $O_2^{-}$: $(17 \ e^-) \rightarrow \dots, \pi^* 2p_x^2 = \pi^* 2p_y^1$ ($1$ unpaired $e^-$) $O_2^{2-}$: $(18 \ e^-) \rightarrow \dots, \pi^* 2p_x^2 = \pi^* 2p_y^2$ ($0$ unpaired $e^-$) $H_2^{+}$: $(1 \ e^-) \rightarrow \sigma 1s^1$ ($1$ unpaired $e^-$) $CN^{-}$: $(14 \ e^-) \rightarrow \dots, \sigma 2p_z^2$ ($0$ unpaired $e^-$) $He_2^{+}$: $(3 \ e^-) \rightarrow \sigma 1s^2, \sigma^* 1s^1$ ($1$ unpaired $e^-$) Species with one unpaired electron are $C_2^{-}, O_2^{-}, H_2^{+}, He_2^{+}$. Total count = $4$.

The total number of species from the following in which one unpaired electron is present,is . . . . . . $N_2, O_2, C_2^{-}, O_2^{-}, O_2^{2-}, H_2^{+}, CN^{-}, He_2^{+}$

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