Give electron configuration, magnetic property bond order and energy diagram for Nitrogen $\left( {{{\rm{N}}_2}} \right)$ molecule.

$\mathrm{N}_{2}(\mathrm{Z}=7) 1 s^{2} 2 s^{2} 2 p^{3}$, total electron in $\mathrm{N}_{2}=14$ and affected valence electron $=10$ Electron configuration in $\mathrm{MO}$ for $\mathrm{N}_{2}$ :

$\mathrm{KK}(\sigma 2 s)^{2}\left(\sigma^{*} 2 s\right)^{2}\left(\pi 2 p_{x}\right)^{2}=\left(\pi 2 p_{y}\right)^{2}\left(\sigma 2 p_{z}\right)^{2} \quad$ OR

$(\sigma 1 s)^{2}\left(\sigma^{*} 1 s\right)^{2}(\sigma 2 s)^{2}\left(\sigma^{*} 2 s\right)^{2}\left(\pi 2 p_{x}\right)^{2}=\left(\pi 2 p_{y}\right)^{2}\left(\sigma 2 p_{z}\right)^{2}$

Bond order $=\frac{1}{2}\left(\mathrm{~N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}\right)=\frac{1}{2}(8-2)=3 \quad$ OR

BO $=\frac{1}{2}\left(\mathrm{~N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}\right)=\frac{1}{2}(10-4)=3$ (Triple bond in $\mathrm{N}_{2}$ )

Magnetic Property : All electrons are paired energy diagram for $\mathrm{N}_{2}$ Molecular