The correct electron affinity order is (EA = | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$ \mathrm{N}  \Rightarrow 1 \mathrm{s}^{2} 2 \mathrm{s}^{2} 2 \mathrm{p}^{3} \Rightarrow \mathrm{N}^{+} \Rightarrow 1 \mathrm{s}^{2} 2 \mathrm{s}

Vedclass · Accepted Answer

${N^ + } > {O^ + } > N{O^ + }$

Vedclass · Answer

$ \mathrm{N}  \Rightarrow 1 \mathrm{s}^{2} 2 \mathrm{s}^{2} 2 \mathrm{p}^{3} \Rightarrow \mathrm{N}^{+} \Rightarrow 1 \mathrm{s}^{2} 2 \mathrm{s}^{2} 2 \mathrm{p}^{2}$

$ \mathrm{O} =1 \mathrm{s}^{2} 2 \mathrm{s}^{2} 2 \mathrm{p}^{4} \Rightarrow \mathrm{O}^{+} \Rightarrow 1 \mathrm{s}^{2} 2 \mathrm{s}^{2} 2 \mathrm{p}^{3} $

$ \mathrm{NO} \Rightarrow \sigma_{1 \mathrm{s}}^{2}, \sigma_{1 \mathrm{s}}^{* 2}, \sigma_{2 \mathrm{s}}^{2}, \sigma_{2 \mathrm{s}}^{* 2}, \pi_{2 \mathrm{py}}^{2}=\pi_{2 \mathrm{p} z}^{2}, \sigma_{2 \mathrm{px}}^{2}, \pi_{2 \mathrm{py}}^{* 1}=\pi_{2 \mathrm{pz}}^{* 0}$

The correct electron affinity order is $(EA = -\Delta H_{EG})$

Similar Questions

Write electron configuration, bond order and Magnetic property of Hydrogen $\left( {{{\rm{H}}_2}} \right)$ molecule.

Which of the following pairs have identical values of bond order ?

A simplified application of $MO$ theory to the hypothitical molecule $'OF'$ would give its bond order as :-

During the formation of a molecular orbital from atomic orbitals, probability of electron density is

In which of the following pairs of molecules/ions, both the species are not likely to exist?