The correct electron affinity order is (EA = | vedclass

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(B) Electron affinity is the energy released when an electron is added to a gaseous species. It is directly related to the stability of the species fo

Vedclass · Accepted Answer

$O^{+} > N^{+} > NO^{+}$

Vedclass · Answer

(B) Electron affinity is the energy released when an electron is added to a gaseous species. It is directly related to the stability of the species formed after electron gain.$N^{+} (1s^{2} 2s^{2} 2p^{2})$: Adding an electron gives $N$ $(1s^{2} 2s^{2} 2p^{3})$,which has a stable half-filled $p$-orbital configuration.$O^{+} (1s^{2} 2s^{2} 2p^{3})$: Adding an electron gives $O$ $(1s^{2} 2s^{2} 2p^{4})$,which is less stable than the half-filled state.$NO^{+}$: This is an isoelectronic species with $N_{2}$ ($14$ electrons). Adding an electron to $NO^{+}$ leads to $NO$ ($15$ electrons),where the electron enters the antibonding $\pi^{*}$ orbital,which is less favorable.Comparing the effective nuclear charge $(Z_{eff})$,$O^{+}$ has a higher $Z_{eff}$ than $N^{+}$,but the stability of the resulting neutral atom is the dominant factor here. The correct order of electron affinity is $O^{+} > N^{+} > NO^{+}$.

The correct electron affinity order is $(EA = -\Delta H_{EG})$

Similar Questions

$A = 1s^2\, 2s^2\, 2p^4$,$B = 1s^2\, 2s^2\, 2p^5$,$C = 1s^2\, 2s^2\, 2p^6$. $A, B$ and $C$ are atoms/anions of the same element. Which one is correct? (One of $A/B/C$ is a neutral atom)

Which of the following represents the correct order of increasing electron gain enthalpy (with negative sign) for the elements?
$a.$ Nitrogen
$b.$ Phosphorus
$c.$ Chlorine
$d.$ Fluorine

Which of the following is correct regarding the electron affinity of halogens?

Which element has the highest electron gain enthalpy?

The formation of the oxide ion $O^{2-}_{(g)}$ requires first an exothermic and then an endothermic step as shown below:
$O_{(g)} + e^{-} \to O^{-}_{(g)}; \Delta H = -142 \, kJ \, mol^{-1}$
$O^{-}_{(g)} + e^{-} \to O^{2-}_{(g)}; \Delta H = 844 \, kJ \, mol^{-1}$
This is because:

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