The area of the square that can be inscribed | vedclass

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Question

Given, radius of circle, $r=O C=8 \,cm$.

$	herefore$ Diameter of the circle $= AC =2 	imes OC =2 	imes 8=16\, cm$

which is equal to the diago

Vedclass · Accepted Answer

$128$

Vedclass · Answer

Given, radius of circle, $r=O C=8 \,cm$.

$	herefore$ Diameter of the circle $= AC =2 	imes OC =2 	imes 8=16\, cm$

which is equal to the diagonal of a square.

Let side of square be $x$.

In right angled $	riangle A B C, \quad A C^{2}=A B^{2}+B C^{2}$ [by Pythagoras theorem]

$\Rightarrow$ $(16)^{2}=x^{2}+x^{2}$

$\Rightarrow$ $256=2 x^{2}$

$\Rightarrow$ $x^{2}=128$

$	herefore$ Afea of square $=x^{2}=128 \, cm ^{2}$

The area of the square that can be inscribed in a circle of radius $8 cm$ is (in $cm ^{2}$)

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