The alkaline hydrolysis of ethyl acetate is represented by the equation $CH_3COOC_2H_5 + NaOH \to CH_3COONa + C_2H_5OH$. Experimentally,it is found that for this reaction $\frac{dx}{dt} = k[CH_3COOC_2H_5][NaOH]$. Then the reaction is
- ABimolecular and of first order
- BBimolecular and of second order
- CPseudo-bimolecular
- DPseudo-unimolecular
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Assertion : The kinetics of the reaction $mA + nB + pC \to m'X + n'Y + p'Z$ obey the rate expression as $\frac{dX}{dt} = k[A]^m[B]^n$.
Reason : The rate of the reaction does not depend upon the concentration of $C$.
Reason : The rate of the reaction does not depend upon the concentration of $C$.
DifficultAIIMS 2017
View SolutionWhy is the hydrolysis of an ester slow at the beginning and fast after some time?
Medium
View SolutionWhich one of the following statements is correct for the reaction?
$CH_3COOC_2H_5(aq) + NaOH(aq) \longrightarrow CH_3COONa(aq) + C_2H_5OH(aq)$
$CH_3COOC_2H_5(aq) + NaOH(aq) \longrightarrow CH_3COONa(aq) + C_2H_5OH(aq)$
$A$ reaction is first order with respect to a reactant $A$ and second order with respect to reactant $B$. What is the effect on the rate when the concentration of both $A$ and $B$ is doubled?
The reaction $A_2 + B_2 \rightarrow 2AB$ follows the mechanism $A_2 \underset{k_{-1}}{\stackrel{k_1}{\rightleftharpoons}} 2A$ (fast),$A + B_2 \xrightarrow{k_2} AB + B$ (slow),$A + B \rightarrow AB$ (fast). The overall order of the reaction is:
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