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(D) For the given reaction: $CH_3COOC_2H_5(aq) + NaOH(aq) \longrightarrow CH_3COONa(aq) + C_2H_5OH(aq)$$1$. Molecularity is defined as the number of r

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Order is two but molecularity is two

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(D) For the given reaction: $CH_3COOC_2H_5(aq) + NaOH(aq) \longrightarrow CH_3COONa(aq) + C_2H_5OH(aq)$$1$. Molecularity is defined as the number of reacting species (atoms,ions,or molecules) taking part in an elementary reaction,which must collide simultaneously in order to bring about a chemical reaction. Here,two molecules ($CH_3COOC_2H_5$ and $NaOH$) are involved,so the molecularity is $2$.$2$. The rate law for this saponification reaction is experimentally determined as: $Rate = k[CH_3COOC_2H_5]^1[NaOH]^1$.$3$. The order of the reaction is the sum of the powers of the concentration terms in the rate law expression,which is $1 + 1 = 2$.Therefore,the reaction is of second order and has a molecularity of $2$.

$Experiment$	$[X] / (mol \ L^{-1})$	$[Y] / (mol \ L^{-1})$	$\text{Initial rate} / (mol \ L^{-1} \ min^{-1})$
$I$	$0.1$	$0.1$	$2 \times 10^{-3}$
$II$	$0.2$	$0.2$	$4 \times 10^{-3}$
$III$	$0.4$	$0.4$	$M \times 10^{-3}$
$IV$	$0.1$	$0.2$	$2 \times 10^{-3}$

Which one of the following statements is correct for the reaction?
$CH_3COOC_2H_5(aq) + NaOH(aq) \longrightarrow CH_3COONa(aq) + C_2H_5OH(aq)$

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Which one of the following statements is correct for the reaction?$CH_3COOC_2H_5(aq) + NaOH(aq) \longrightarrow CH_3COONa(aq) + C_2H_5OH(aq)$