The acceleration of a moving body can be found from
The acceleration of a moving body can be found from
- A
Area under velocity-time graph
- B
Area under distance-time graph
- C
Slope of the velocity-time graph
- D
Slope of distance-time graph
Similar Questions
If velocity of particle moving along $x-$ axis is given as $v = k\sqrt x $ . Then ($a$ is acceleration)
If velocity of particle moving along $x-$ axis is given as $v = k\sqrt x $ . Then ($a$ is acceleration)
A particle of unit mass undergoes one dimensional motion such that its velocity varies according to $ v(x)= \beta {x^{ - 2n}}$, where $\beta$ and $n$ are constants and $x$ is the position of the particle. The acceleration of the particle as a function of $x$, is given by
A particle of unit mass undergoes one dimensional motion such that its velocity varies according to $ v(x)= \beta {x^{ - 2n}}$, where $\beta$ and $n$ are constants and $x$ is the position of the particle. The acceleration of the particle as a function of $x$, is given by
- [AIPMT 2015]
The displacement of a particle moving in a straight line depends on time as $x=\alpha t^3+\beta t^2+\gamma t+\delta$.The ratio of initial acceleration to its initial velocity depends
In the $s-t$ equation $\left(s=10+20 t-5 t^2\right)$, match the following columns.
Colum $I$
Colum $II$
$(A)$ Distance travelled in $3\,s$
$(p)$ $-20$ units
$(B)$ Displacement in $1\,s$
$(q)$ $15$ units
$(C)$ Initial acceleration
$(r)$ $25$ units
$(D)$ Velocity at $4\,s$
$(s)$ $-10$ units
| Colum $I$ | Colum $II$ |
| $(A)$ Distance travelled in $3\,s$ | $(p)$ $-20$ units |
| $(B)$ Displacement in $1\,s$ | $(q)$ $15$ units |
| $(C)$ Initial acceleration | $(r)$ $25$ units |
| $(D)$ Velocity at $4\,s$ | $(s)$ $-10$ units |
Draw $x \to t$ graph for negative acceleration.
Draw $x \to t$ graph for negative acceleration.