The displacement of a particle moving in a straight line depends on time as $x=\alpha t^3+\beta t^2+\gamma t+\delta$.The ratio of initial acceleration to its initial velocity depends

  • A
    only on $\alpha$ and $\gamma$
  • B
    only on $\beta$ and $\gamma$
  • C
    only on $\alpha$ and $\beta$
  • D
    only on $\alpha$

Similar Questions

Two particles $A$ and $B$ start from rest and move for equal time on a straight line. Particle $A$ has an acceleration of $2\,m / s ^2$ for the first half of the total time and $4\,m / s ^2$ for the second half. The particle $B$ has acceleration $4\,m / s ^2$ for the first half and $2\,m / s ^2$ for the second half. Which particle has covered larger distance?

The graph shows the variation with time $t$ of velocity $v$ of an object moving along a straight line. $a-t$ graph will be

A particle moves in a straight line so that its displacement $x$ at any time $t$ is given by $x^2=1+t^2$. Its acceleration at any time $\mathrm{t}$ is $\mathrm{x}^{-\mathrm{n}}$ where $\mathrm{n}=$ . . . . .

  • [JEE MAIN 2024]

Velocity of a particle is in negative direction with constant acceleration in positive direction. Then, match the following columns.

Colum $I$ Colum $II$
$(A)$ Velocity-time graph $(p)$ Slope $\rightarrow$ negative
$(B)$ Acceleration-time graph $(q)$ Slope $\rightarrow$ positive
$(C)$ Displacement-time graph $(r)$ Slope $\rightarrow$ zero
  $(s)$ $\mid$ Slope $\mid \rightarrow$ increasing
  $(t)$ $\mid$ Slope $\mid$ $\rightarrow$ decreasing
  $(u)$ |Slope| $\rightarrow$ constant

What determines the nature of the path followed by the particle