The acceleration of a body due to the attraction of the earth (radius $R$) at a distance $2 \,R$ from the surface of the earth is ($g =$ acceleration due to gravity at the surface of the earth)
The acceleration of a body due to the attraction of the earth (radius $R$) at a distance $2 \,R$ from the surface of the earth is ($g =$ acceleration due to gravity at the surface of the earth)
- A
$\frac{g}{9}$
- B
$\frac{g}{3}$
- C
$\frac{g}{4}$
- D
$g$
Similar Questions
Obtain an expression for the variation in effective gravitational acceleration $g'$ with latitude due to earth’s rotation.
Obtain an expression for the variation in effective gravitational acceleration $g'$ with latitude due to earth’s rotation.
The mass and diameter of a planet are twice those of earth. What will be the period of oscillation of a pendulum on this planet if it is a seconds pendulum on earth ?
The mass and diameter of a planet are twice those of earth. What will be the period of oscillation of a pendulum on this planet if it is a seconds pendulum on earth ?
Given below are two statements :
Statement $I$ : The law of gravitation holds good for any pair of bodies in the universe.
Statement $II$ : The weight of any person becomes zero when the person is at the centre of the earth. In the light of the above statements, choose the correct answer from the options given below.
Given below are two statements :
Statement $I$ : The law of gravitation holds good for any pair of bodies in the universe.
Statement $II$ : The weight of any person becomes zero when the person is at the centre of the earth. In the light of the above statements, choose the correct answer from the options given below.
- [JEE MAIN 2022]
A spherical planet has a mass $M$ and diameter $D$ . A particle of mass $m$ falling freely near the surface of this planet will experience an acceleration due to gravity , equal to
A spherical planet has a mass $M$ and diameter $D$ . A particle of mass $m$ falling freely near the surface of this planet will experience an acceleration due to gravity , equal to
- [AIPMT 2012]
A planet of radius $R =\frac{1}{10} \times$ (radius of Earth) has the same mass density as Earth. Scientists dig a well of depth $\frac{R}{5}$ on it and lower a wire of the same length and of linear mass density $10^{-3} \ kgm ^{-1}$ into it. If the wire is not touching anywhere, the force applied at the top of the wire by a person holding it in place is (take the radius of Earth $=6 \times 10^6 \ m$ and the acceleration due to gravity on Earth is $10 \ ms ^{-2}$ )
A planet of radius $R =\frac{1}{10} \times$ (radius of Earth) has the same mass density as Earth. Scientists dig a well of depth $\frac{R}{5}$ on it and lower a wire of the same length and of linear mass density $10^{-3} \ kgm ^{-1}$ into it. If the wire is not touching anywhere, the force applied at the top of the wire by a person holding it in place is (take the radius of Earth $=6 \times 10^6 \ m$ and the acceleration due to gravity on Earth is $10 \ ms ^{-2}$ )
- [IIT 2014]