A spherical planet has a mass M and diameter | vedclass

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(A) The gravitational force $F$ acting on a particle of mass $m$ near the surface of a planet of mass $M$ and radius $R = D/2$ is given by Newton's la

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$\frac{4GM}{D^2}$

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(A) The gravitational force $F$ acting on a particle of mass $m$ near the surface of a planet of mass $M$ and radius $R = D/2$ is given by Newton's law of gravitation:$F = \frac{GMm}{R^2} = \frac{GMm}{(D/2)^2}$The acceleration due to gravity $g$ experienced by the particle is defined as the force per unit mass:$g = \frac{F}{m} = \frac{GM}{(D/2)^2}$Simplifying the expression:$g = \frac{GM}{D^2/4} = \frac{4GM}{D^2}$Thus,the acceleration due to gravity is $\frac{4GM}{D^2}$.

$A$ spherical planet has a mass $M$ and diameter $D$. $A$ particle of mass $m$ falling freely near the surface of this planet will experience an acceleration due to gravity equal to:

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