State whether the following statement is true:

There is a number $x$ such that $x^{2}$ is irrational but $x^{4}$ is rational. Justify your answer by an example.

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True,

Let us take $x=\sqrt[4]{2}$

Now, $\quad x^{2}=(\sqrt[4]{2})^{2}=\sqrt{2},$ an irrational number.

$x^{4}=(\sqrt[4]{2})^{4}=2,$ a rational number.

So, we have a number $x$ such that $x^{2}$ is irrational but $x^{4}$ is rational.

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