The value of frac{sqrt{32}+sqrt{48}}{sqrt{8}+ | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}=\frac{\sqrt{16 	imes 2}+\sqrt{16 	imes 3}}{\sqrt{4 	imes 2}+\sqrt{4 	imes 3}}$

$=\frac{4 \sqrt{

Vedclass · Accepted Answer

$2$

Vedclass · Answer

$\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}=\frac{\sqrt{16 	imes 2}+\sqrt{16 	imes 3}}{\sqrt{4 	imes 2}+\sqrt{4 	imes 3}}$

$=\frac{4 \sqrt{2}+4 \sqrt{3}}{2 \sqrt{2}+2 \sqrt{3}}=\frac{4(\sqrt{2}+\sqrt{3})}{(2 \sqrt{2}+\sqrt{3})}=\frac{4}{2}=2$

Hence, $(d)$ is the correct answer.

The value of $\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}$ is equal to

Similar Questions

Prove that

$\left(\frac{x^{a}}{x^{b}}\right)^{a+b} \times\left(\frac{x^{b}}{x^{c}}\right)^{b+c} \times\left(\frac{x^{c}}{x^{a}}\right)^{c+a}=1$

Represent geometrically numbers on the number line:

$\sqrt{2.3}$

Find the value

$64^{\frac{5}{6}}$

Rationalise the denominator in each of the following and hence evaluate by taking $\sqrt{2}=1.414, \sqrt{3}=1.732$ and $\sqrt{5}=2.236,$ upto three places of decimal.

$\frac{1}{\sqrt{3}+\sqrt{2}}$

State whether each of the following statements is true or false

$(-1)^{11}=-1$

The value of $\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}$ is equal to

Similar Questions

Prove that $\left(\frac{x^{a}}{x^{b}}\right)^{a+b} \times\left(\frac{x^{b}}{x^{c}}\right)^{b+c} \times\left(\frac{x^{c}}{x^{a}}\right)^{c+a}=1$

Represent geometrically numbers on the number line: $\sqrt{2.3}$

Find the value $64^{\frac{5}{6}}$

Rationalise the denominator in each of the following and hence evaluate by taking $\sqrt{2}=1.414, \sqrt{3}=1.732$ and $\sqrt{5}=2.236,$ upto three places of decimal. $\frac{1}{\sqrt{3}+\sqrt{2}}$

State whether each of the following statements is true or false $(-1)^{11}=-1$

Prove that

$\left(\frac{x^{a}}{x^{b}}\right)^{a+b} \times\left(\frac{x^{b}}{x^{c}}\right)^{b+c} \times\left(\frac{x^{c}}{x^{a}}\right)^{c+a}=1$

Represent geometrically numbers on the number line:

$\sqrt{2.3}$

Find the value

$64^{\frac{5}{6}}$

Rationalise the denominator in each of the following and hence evaluate by taking $\sqrt{2}=1.414, \sqrt{3}=1.732$ and $\sqrt{5}=2.236,$ upto three places of decimal.

$\frac{1}{\sqrt{3}+\sqrt{2}}$

State whether each of the following statements is true or false

$(-1)^{11}=-1$