Factorise :
$x^{3}-6 x^{2}+11 x-6$
Without actually calculating the cubes, find the value of each of the following
$(31)^{3}-(16)^{3}-(15)^{3}$
Factorise :
$x^{3}+x^{2}-4 x-4$
Evaluate the following using suitable identities
$(105)^{3}$
Factorise $: 121 x^{2}-289 y^{2}$