Spin only magnetic moment of [MnBr_{6}]^{4-} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In $[MnBr_{6}]^{4-}$,the oxidation state of $Mn$ is $+2$.Electronic configuration of $Mn^{2+}$ is $[Ar] 3d^{5}$.Since $Br^{-}$ is a weak field lig

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(B) In $[MnBr_{6}]^{4-}$,the oxidation state of $Mn$ is $+2$.Electronic configuration of $Mn^{2+}$ is $[Ar] 3d^{5}$.Since $Br^{-}$ is a weak field ligand,the electrons remain unpaired in the $d$-orbitals.Number of unpaired electrons $(n)$ = $5$.The spin-only magnetic moment is calculated as $\mu = \sqrt{n(n+2)} \ B.M.$$\mu = \sqrt{5(5+2)} = \sqrt{35} \approx 5.91 \ B.M.$Rounding off to the closest integer,we get $6 \ B.M.$

Spin only magnetic moment of $[MnBr_{6}]^{4-}$ is $..... \ B.M.$ (round off to the closest integer)

Similar Questions

In a $d^4$ low spin complex,what will be the magnetic moment $(\mu)$ in $B.M.$ if the coordination number is $6$?

The spin-only magnetic moment of an octahedral complex of $Fe^{2+}$ in the presence of a strong field ligand in $B.M.$ is $.....$

Identify the ion (hydrated in solution) which is not correctly matched with its spin only magnetic moment (in $BM$) given in brackets.

What is the magnetic moment of $[FeF_6]^{3-}$ (in $BM$)?

Which of the following will have three stereoisomeric forms?
$(i) \ [Cr(NO_3)_3(NH_3)_3]$
$(ii) \ K_3[Co(C_2O_4)_3]$
$(iii) \ K_3[CoCl_2(C_2O_4)_2]$
$(iv) \ [CoBrCl(en)_2]$

Vedclass Test Series

Exam Paper Generator

Online Exam Module