The spin-only magnetic moment of an octahedra | vedclass

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(B) The electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6$.In the presence of a strong field ligand $(SFL)$,the crystal field splitting energy $\Del

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(B) The electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6$.In the presence of a strong field ligand $(SFL)$,the crystal field splitting energy $\Delta_0$ is greater than the pairing energy $P$ $(\Delta_0 > P)$.This causes the electrons to pair up in the $t_{2g}$ orbitals.The distribution of electrons in the $t_{2g}$ orbitals is $(t_{2g})^6 (e_g)^0$.Since all electrons are paired,the number of unpaired electrons $(n)$ is $0$.The spin-only magnetic moment $\mu$ is calculated as $\mu = \sqrt{n(n+2)} \ B.M.$Substituting $n = 0$,we get $\mu = \sqrt{0(0+2)} = 0 \ B.M.$

The spin-only magnetic moment of an octahedral complex of $Fe^{2+}$ in the presence of a strong field ligand in $B.M.$ is $.....$

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