Which of the following will have three stereo | vedclass

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(C) To determine the number of stereoisomeric forms,we analyze each complex:$(i) \ [Cr(NO_3)_3(NH_3)_3]$ is of the type $[MA_3B_3]$. It exhibits facia

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$(iii)$ and $(iv)$

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(C) To determine the number of stereoisomeric forms,we analyze each complex:$(i) \ [Cr(NO_3)_3(NH_3)_3]$ is of the type $[MA_3B_3]$. It exhibits facial $(fac)$ and meridional $(mer)$ geometric isomerism. It does not show optical isomerism. Thus,it has $2$ stereoisomers.$(ii) \ K_3[Co(C_2O_4)_3]$ is of the type $[M(AA)_3]$. It shows optical isomerism ($d$ and $l$ forms). It has $2$ stereoisomers.$(iii) \ K_3[CoCl_2(C_2O_4)_2]$ is of the type $[M(AA)_2B_2]$. The cis-isomer is optically active ($d$ and $l$ forms),while the trans-isomer is optically inactive (meso-form). Thus,it has $3$ stereoisomers $(d, l, 	ext{and } trans)$.$(iv) \ [CoBrCl(en)_2]$ is of the type $[M(AA)_2BC]$. The cis-isomer is optically active ($d$ and $l$ forms),while the trans-isomer is optically inactive (meso-form). Thus,it has $3$ stereoisomers $(d, l, 	ext{and } trans)$.Therefore,$(iii)$ and $(iv)$ have three stereoisomeric forms.

Which of the following will have three stereoisomeric forms?
$(i) \ [Cr(NO_3)_3(NH_3)_3]$
$(ii) \ K_3[Co(C_2O_4)_3]$
$(iii) \ K_3[CoCl_2(C_2O_4)_2]$
$(iv) \ [CoBrCl(en)_2]$

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Which of the following will have three stereoisomeric forms?$(i) \ [Cr(NO_3)_3(NH_3)_3]$$(ii) \ K_3[Co(C_2O_4)_3]$$(iii) \ K_3[CoCl_2(C_2O_4)_2]$$(iv) \ [CoBrCl(en)_2]$