What is the magnetic moment of [FeF_6]^{3-} ( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In $[FeF_6]^{3-}$,the oxidation state of $Fe$ is $+3$.The electronic configuration of $Fe^{3+}$ is $[Ar] \ 3d^5$.Since $F^-$ is a weak field ligan

Vedclass · Accepted Answer

$5.92$

Vedclass · Answer

(A) In $[FeF_6]^{3-}$,the oxidation state of $Fe$ is $+3$.The electronic configuration of $Fe^{3+}$ is $[Ar] \ 3d^5$.Since $F^-$ is a weak field ligand,it does not cause pairing of electrons.Thus,there are $5$ unpaired electrons $(n = 5)$.The magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$.$\mu = \sqrt{5(5+2)} = \sqrt{35} \approx 5.92 \ BM$.

What is the magnetic moment of $[FeF_6]^{3-}$ (in $BM$)?

Similar Questions

Which of the following is not a coordination isomer of $[Cr(NH_3)_6][CoCl_6]$?

Give an example of ionization isomerism.

The number of isomers possible for the square planar complex $K_2[PdClBr_2(SCN)]$ is

Which compound has a magnetic moment equal to $4.90 \ B.M.$?

Identify the homoleptic complex(es) that is/are low spin.
$(A) \ [Fe(CN)_5NO]^{2-}$
$(B) \ [CoF_6]^{3-}$
$(C) \ [Fe(CN)_6]^{4-}$
$(D) \ [Co(NH_3)_6]^{3+}$
$(E) \ [Cr(H_2O)_6]^{2+}$
Choose the correct answer from the options given below:

Vedclass Test Series

Exam Paper Generator

Online Exam Module