Shown below is a distribution of charges. The flux of electric field due to these charges through the surface $S$ is

$A$ linear charge having linear charge density $\lambda$ penetrates a cube diagonally and then it penetrates a sphere diametrically as shown. What will be the ratio of flux coming out of the cube and the sphere?

Electric flux through a surface of area $100 \ m^2$ lying in the $xy$ plane is (in $V-m$) if $\vec E = \hat i + \sqrt 2 \hat j + \sqrt 3 \hat k$.

$A$ positive charge $Q$ is situated at the centre of a cube. The electric flux through any face of the cube is (in $SI$ units)

If $\oint_s \vec{E} \cdot \overrightarrow{d S}=0$ over a surface,then:

It is not convenient to use a spherical Gaussian surface to find the electric field due to an electric dipole using Gauss's theorem because