Show that a force that does no work must be a velocity dependent force.
As work done by force is zero,
$\therefore d \mathrm{~W}=\overrightarrow{\mathrm{F}} \cdot \overrightarrow{d l}=0$
$\therefore \overrightarrow{\mathrm{F}} \cdot \overrightarrow{d l} \cdot d t$
$\therefore \overrightarrow{\mathrm{F}} \cdot(\vec{v} \cdot \overrightarrow{d l})=0$
$\therefore \overrightarrow{\mathrm{F}} \cdot \vec{v}=0, d l \neq 0$
$\therefore$ F $v \cos \theta=0$
If $v$ changes direction then to make $\theta=90, \mathrm{~F}$ must charne angle according to $v .$ So, $\mathrm{F}$ is dependent on $v$ to make work done zero.
An electron enters a chamber in which an uniform magnetic field is present as shown in figure. Ignore gravity. During its motion inside the chamber
A deuteron and a proton moving with equal kinetic energy enter into to a uniform magnetic field at right angle to the field. If $r_{d}$ and $r_{p}$ are the radii of their circular paths respectively, then the ratio $\frac{r_{d}}{r_{p}}$ will be $\sqrt{ x }: 1$ where $x$ is ..........
Consider the following statements regarding a charged particle in a magnetic field . Which of the statements are true :
In an experiment, electrons are accelerated, from rest, by applying, a voltage of $500 \,V.$ Calculate the radius of the path if a magnetic field $100\,mT$ is then applied. [Charge of the electron $= 1.6 \times 10^{-19}\,C$ Mass of the electron $= 9.1 \times 10^{-31}\,kg$ ]
A uniform electric field and a uniform magnetic field are produced, pointed in the same direction. An electron is projected with its velocity pointing in the same direction