Consider the following statements regarding a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The magnetic Lorentz force on a charged particle moving with velocity $\vec{v}$ in a magnetic field $\vec{B}$ is given by $\vec{F} = q(\vec{v} 	i

Vedclass · Accepted Answer

Both $(B)$ and $(C)$

Vedclass · Answer

(D) The magnetic Lorentz force on a charged particle moving with velocity $\vec{v}$ in a magnetic field $\vec{B}$ is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$.Statement $(A)$ is false because if the initial velocity is zero,the magnetic force $\vec{F} = q(0 	imes \vec{B}) = 0$. Thus,it does not accelerate.Statement $(B)$ is true because the magnetic force is the cross product of $\vec{v}$ and $\vec{B}$,which is always perpendicular to both $\vec{v}$ and $\vec{B}$.Statement $(C)$ is true because the force magnitude is $F = qvB \sin 	heta$,where $	heta$ is the angle between $\vec{v}$ and $\vec{B}$. This is equivalent to $F = qv(B \sin 	heta)$,where $B \sin 	heta$ is the component of the magnetic field perpendicular to the velocity.Therefore,both $(B)$ and $(C)$ are correct.

Consider the following statements regarding a charged particle in a magnetic field. Which of the statements are true?

Similar Questions

$A$ proton, a deuteron (nucleus of ${ }_1 H^2$) and an $\alpha$-particle with the same kinetic energy enter a region of uniform magnetic field moving at right angles to the field. The ratio of the radii of their circular paths is:

The following figure shows the path of an electron that passes through two regions containing uniform magnetic fields of magnitudes $B_1$ and $B_2$. Its path in each region is a half-circle. Choose the correct option.

$A$ mixed beam of $He^+$ and $O^{2+}$ ions (mass of $He^+ = 4 \ amu$ and that of $O^{2+} = 16 \ amu$) passes through a region of a constant perpendicular magnetic field. If the kinetic energy of all the ions is the same,then:

$A$ beam of protons moving with a velocity $1.6 \times 10^5 \ m/s$ enters a uniform magnetic field of $\frac{\pi}{10} \ T$ at an angle $60^{\circ}$ to the direction of the field. The pitch of the helical path of the protons is (mass of proton $= 1.6 \times 10^{-27} \ kg$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module