Consider the following statements regarding a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The magnetic Lorentz force on a charged particle moving with velocity $\vec{v}$ in a magnetic field $\vec{B}$ is given by $\vec{F} = q(\vec{v} 	i

Vedclass · Accepted Answer

Both $(B)$ and $(C)$

Vedclass · Answer

(D) The magnetic Lorentz force on a charged particle moving with velocity $\vec{v}$ in a magnetic field $\vec{B}$ is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$.Statement $(A)$ is false because if the initial velocity is zero,the magnetic force $\vec{F} = q(0 	imes \vec{B}) = 0$. Thus,it does not accelerate.Statement $(B)$ is true because the magnetic force is the cross product of $\vec{v}$ and $\vec{B}$,which is always perpendicular to both $\vec{v}$ and $\vec{B}$.Statement $(C)$ is true because the force magnitude is $F = qvB \sin 	heta$,where $	heta$ is the angle between $\vec{v}$ and $\vec{B}$. This is equivalent to $F = qv(B \sin 	heta)$,where $B \sin 	heta$ is the component of the magnetic field perpendicular to the velocity.Therefore,both $(B)$ and $(C)$ are correct.

Consider the following statements regarding a charged particle in a magnetic field. Which of the statements are true?

Similar Questions

An electron $(e^-)$ is moving in the North direction and the magnetic field at this place is in the upward direction. Then,the electron $(e^-)$ will be deviated towards:

If a proton enters perpendicularly into a magnetic field with velocity $v$,the time period of revolution is $T$. If the proton enters with velocity $2v$,what will be the time period?

An electron is moving in a circle of radius $r$ in a magnetic field $B$. Suddenly,the field is reduced to $B/2$. The radius of the circular path is

An electron,moving in a uniform magnetic field of induction of intensity $\vec{B}$,has its radius directly proportional to

Vedclass Test Series

Exam Paper Generator

Online Exam Module