A uniform electric field and a uniform magnet | vedclass

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(D) The magnetic force on a moving charge is given by $\vec{F}_m = q(\vec{v} 	imes \vec{B})$. Since the electron is moving parallel to the magnetic f

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The electron velocity will decrease in magnitude.

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(D) The magnetic force on a moving charge is given by $\vec{F}_m = q(\vec{v} 	imes \vec{B})$. Since the electron is moving parallel to the magnetic field,the angle between $\vec{v}$ and $\vec{B}$ is $0^\circ$,so $\vec{F}_m = 0$.The electric force on the electron is given by $\vec{F}_e = q\vec{E}$. Since the charge of an electron is negative $(q = -e)$,the electric force acts in the direction opposite to the electric field $\vec{E}$.As the electron is projected in the direction of the electric field,the electric force acts in the opposite direction to its velocity. This force acts as a retarding force,causing the electron to decelerate. Therefore,the magnitude of the electron's velocity will decrease.

$A$ uniform electric field and a uniform magnetic field are produced,pointing in the same direction. An electron is projected with its velocity pointing in the same direction.

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