Show that $1.272727 \ldots=1 . \overline{27}$ . can be expressed in the form $\frac {p }{q }$, where $p$ and $q$ are integers and $q \ne 0$.
Let $x=1.272727 \ldots$ since two digits are repeating, we multiply $x$ by $100$ to get
$100 x=127.2727 \ldots$
So, $100 x=126+1.272727 \ldots=126+x$
Therefore, $100 x-x=126,$ i.e., $99 x=126$
i.e., $x=\frac{126}{99}=\frac{14}{11}$
You can check the reverse that $\frac{14}{11}=1 . \overline{27}$
Classify the following numbers as rational or irrational :
$(i)$ $2-\sqrt{5}$
$(ii)$ $(3+\sqrt{23})-\sqrt{23}$
$(iii)$ $\frac{2 \sqrt{7}}{7 \sqrt{7}}$
$(iv)$ $\frac{1}{\sqrt{2}}$
$(v)$ $2 \pi$
Add $2 \sqrt{2}+5 \sqrt{3}$ and $\sqrt{2}-3 \sqrt{3}$
Find the decimal expansions of $\frac{10}{3},\, \frac{7}{8}$ and $\frac{1}{7}$.
Rationalise the denominator of $\frac{1}{\sqrt{2}}$.
Express $0.99999 \ldots$ in the form $\frac{p}{q}$. Are you surprised by your answer ? With your teacher and classmates discuss why the answer makes sense.