Express $0.99999 \ldots$ in the form $\frac{p}{q}$. Are you surprised by your answer ? With your teacher and classmates discuss why the answer makes sense.

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Let $x=0.9999 \ldots$

Multiply both sides by $10,$ we have                                          $[\because$ There is only one repeating digit.]

$10 \times x =10 \times(0.99999 \ldots)$

or                 $10 x=9.9999 \ldots$

Subtracting $(1)$ from $(2)$, we get

$10 x-x=(9.9999 \ldots)-(0.9999 \ldots)$

or               $9 x=9$    

or                $x=\frac{9}{9}=1$

Thus, $\quad 0.9999 \ldots=1$

As $0.9999 \ldots$ goes on forever, there is no gap between $1$ and $0.9999 \ldots$

Hence both are equal.

Similar Questions

Find :

$(i)$ $9^{\frac{3}{2}}$

$(ii)$ $32^{\frac{2}{5}}$

$(iii)$ $16^{\frac{3}{4}}$

$(iv)$ $125^{\frac{-1}{3}}$

Find an irrational number between $\frac {1}{7}$ and $\frac {2}{7}$

Express the following in the form $\frac {p}{q}$, where $p$ and $q$ are integers and $q \ne 0$.

$(i)$ $0 . \overline{6}$

$(ii)$ $0 . 4\overline{7}$

$(iii)$ $0 . \overline{001}$

State whether the following statements are true or false. Justify your answers.

$(i)$ Every irrational number is a real number.

$(ii)$ Every point on the number line is of the form $\sqrt m$ , where $m$ is a natural number.

$(iii)$ Every real number is an irrational number.

Represent $ \sqrt{9.3}$ on the number line.