Represent geometrically numbers on the number line:

$\sqrt{2.3}$

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Mark the distance $2.3$ units from a fixed points $A$ on a given line to obtain a point $B$ such that $AB =2.3$ units. From $B$ mark, a distance of $1$ unit and mark the new point as $C$. Find the mid-point of $AC$ and mark that point as $0 .$ Draw a semicircle with centre $0$ and radius $OC.$ Draw a line perpendicular to $AC$ passing through $B$ and intersecting the semicircle at $D.$ Then, $B D=\sqrt{2.3}$.

Now, draw an arc with centre $B$ and radius $BD$, which intersects the number line in $E$. Thus,$E$ represents $\sqrt{2.3}$

1099-s61

Similar Questions

Find three different irrational numbers lying between $\sqrt{3}$ and $\sqrt{5}$.

Represent geometrically numbers on the number line:

$\sqrt{4.5}$

Rationalise the denominator in each of the following and hence evaluate by taking $\sqrt{2}=1.414, \sqrt{3}=1.732$ and $\sqrt{5}=2.236,$ upto three places of decimal.

$\frac{6}{\sqrt{6}}$

Classify the following numbers as rational or irrational with justification:

$(i)$ $\sqrt{196}$

$(ii)$ $3 \sqrt{18}$

Express the following in the form $\frac{p}{q},$ where $p$ and $q$ are integers and $q \neq 0 .$

$0.5 \overline{7}$