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(A) To rationalise the denominator of $\frac{4}{\sqrt{10}+\sqrt{6}}$,multiply the numerator and the denominator by the conjugate of the denominator,wh

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$\sqrt{10}-\sqrt{6}$

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(A) To rationalise the denominator of $\frac{4}{\sqrt{10}+\sqrt{6}}$,multiply the numerator and the denominator by the conjugate of the denominator,which is $(\sqrt{10}-\sqrt{6})$.$\frac{4}{\sqrt{10}+\sqrt{6}} 	imes \frac{\sqrt{10}-\sqrt{6}}{\sqrt{10}-\sqrt{6}}$$= \frac{4(\sqrt{10}-\sqrt{6})}{(\sqrt{10})^2 - (\sqrt{6})^2}$$= \frac{4(\sqrt{10}-\sqrt{6})}{10-6}$$= \frac{4(\sqrt{10}-\sqrt{6})}{4}$$= \sqrt{10}-\sqrt{6}$

Rationalise the denominator of the following expression:
$\frac{4}{\sqrt{10}+\sqrt{6}}$

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Rationalise the denominator of the following expression:$\frac{4}{\sqrt{10}+\sqrt{6}}$