Prussian blue is due to the formation of

  • [AIPMT 1990]
  • A

    $F{e_4}{\left[ {Fe{{(CN)}_6}} \right]_3}$

  • B

    $F{e_2}\left[ {Fe{{(CN)}_6}} \right]$

  • C

    $F{e_3}\left[ {Fe{{(CN)}_6}} \right]$

  • D

    $Fe{\left[ {Fe{{(CN)}_6}} \right]_3}$

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