The melting point of Zn is lower as compared | vedclass

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(A) The melting point of transition elements depends on the strength of metallic bonding,which is determined by the number of unpaired electrons avail

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The $d$-orbitals are completely filled

Vedclass · Answer

(A) The melting point of transition elements depends on the strength of metallic bonding,which is determined by the number of unpaired electrons available for delocalization.In the $3d$ series,$Zn$ has the electronic configuration $[Ar] 3d^{10} 4s^2$.Since all $d$-orbitals are completely filled,there are no unpaired electrons available for metallic bonding.Consequently,the interatomic metallic bonding in $Zn$ is relatively weak,leading to a lower melting point compared to other $3d$ transition elements.

$I. \ Zn^{2+}$	$(i) \ d^8 \ \text{configuration}$
$II. \ Cu^{2+}$	$(ii) \ \text{Colourless}$
$III. \ Ni^{2+}$	$(iii) \ \mu = 1.73 \ \text{BM}$

The melting point of $Zn$ is lower as compared to those of the other elements of the $3d$ series because:

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Match the following:
$I. \ Zn^{2+}$ $(i) \ d^8 \ \text{configuration}$
$II. \ Cu^{2+}$ $(ii) \ \text{Colourless}$
$III. \ Ni^{2+}$ $(iii) \ \mu = 1.73 \ \text{BM}$

Transition elements are:

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