Out of four numbers,whose average is 60,the f | vedclass

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Question

(C) Let the four numbers be $a, b, c,$ and $d$.Given that the average of the four numbers is $60$,so their sum is $a + b + c + d = 60 	imes 4 = 240$.

Vedclass · Accepted Answer

$48$

Vedclass · Answer

(C) Let the four numbers be $a, b, c,$ and $d$.Given that the average of the four numbers is $60$,so their sum is $a + b + c + d = 60 	imes 4 = 240$.According to the problem,the first number $a$ is one-fourth of the sum of the last three numbers $(b + c + d)$.So,$a = \frac{1}{4}(b + c + d)$,which implies $b + c + d = 4a$.Substitute this into the sum equation: $a + (b + c + d) = 240$.$a + 4a = 240$.$5a = 240$.$a = \frac{240}{5} = 48$.Therefore,the first number is $48$.

Out of four numbers,whose average is $60$,the first one is one-fourth of the sum of the last three. The first number is

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