The bowling average of a cricketer was 12.4. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the number of wickets taken by the cricketer before the last match be $x$.The total runs conceded before the last match $= 12.4x$.In the last

Vedclass · Accepted Answer

$175$

Vedclass · Answer

(C) Let the number of wickets taken by the cricketer before the last match be $x$.The total runs conceded before the last match $= 12.4x$.In the last match,he took $5$ wickets for $26$ runs.New total wickets $= x + 5$.New total runs $= 12.4x + 26$.The new bowling average is $12.4 - 0.2 = 12.2$.According to the problem:$\frac{12.4x + 26}{x + 5} = 12.2$$12.4x + 26 = 12.2(x + 5)$$12.4x + 26 = 12.2x + 61$$12.4x - 12.2x = 61 - 26$$0.2x = 35$$x = \frac{35}{0.2} = 175$.Therefore,the number of wickets taken before the last match was $175$.

The bowling average of a cricketer was $12.4$. He improves his bowling average by $0.2$ points when he takes $5$ wickets for $26$ runs in his last match. The number of wickets taken by him before the last match was?

Similar Questions

In a $20$ over match,the required run rate to win is $7.2$. If the run rate is $6$ at the end of the $15^{th}$ over,the required run rate to win the match is

If the average of $6$ consecutive even numbers is $25,$ the difference between the largest and the smallest number is

The average marks obtained by $40$ students of a class is $86$. If the $5$ highest marks are removed,the average reduces by $1$ mark. The average marks of the top $5$ students is

The average speed of a train running at a speed of $30 \, km/h$ during the first $100 \, km$,at $40 \, km/h$ during the second $100 \, km$,and at $50 \, km/h$ during the last $100 \, km$ is nearly (in $km/h$):

What was the average daily expenditure in $Rs.$ of a man in $1999$ who spent $Rs. \, 76535$ in the first half of the year and $Rs. \, 88165$ in the second half?

Vedclass Test Series

Exam Paper Generator

Online Exam Module