A cricketer,whose bowling average was 12.4 ru | vedclass

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(C) Let the number of wickets taken by the cricketer before this match be $w$.Total runs conceded before this match = $12.4w$.In the current match,he

Vedclass · Accepted Answer

$95$

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(C) Let the number of wickets taken by the cricketer before this match be $w$.Total runs conceded before this match = $12.4w$.In the current match,he takes $5$ wickets for $22$ runs.Total wickets after the match = $w + 5$.Total runs after the match = $12.4w + 22$.The new average is $12.4 - 0.4 = 12.0$ runs/wicket.According to the problem:$\frac{12.4w + 22}{w + 5} = 12.0$$12.4w + 22 = 12(w + 5)$$12.4w + 22 = 12w + 60$$12.4w - 12w = 60 - 22$$0.4w = 38$$w = \frac{38}{0.4} = 95$.Thus,the number of wickets taken before this match was $95$.

$A$ cricketer,whose bowling average was $12.4$ runs/wicket,takes $5$ wickets for $22$ runs in a match,thereby decreasing his average by $0.4$. The number of wickets taken by him before this match was:

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