One side of a rectangle lies along the line $4x + 7y + 5 = 0.$ Two of its vertices are $(-3, 1)$ and $(1, 1)$. Then the equations of other three sides are
One side of a rectangle lies along the line $4x + 7y + 5 = 0.$ Two of its vertices are $(-3, 1)$ and $(1, 1)$. Then the equations of other three sides are
- [IIT 1978]
- A
$7x - 4y + 25 = 0,$$4x + 7y = 11$ and $7x - 4y - 3 = 0$
- B
$7x + 4y + 25 = 0,$$7y + 4x - 11 = 0$ and $7x - 4y - 3 = 0$
- C
$4x - 7y + 25 = 0,$$7x + 4y - 11 = 0$ and $4x - 7y - 3 = 0$
- D
None of these
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