In a high school,a committee has to be formed from a group of $6$ boys $M_1, M_2, M_3, M_4, M_5, M_6$ and $5$ girls $G_1, G_2, G_3, G_4, G_5$.
$(i)$ Let $\alpha_1$ be the total number of ways in which the committee can be formed such that the committee has $5$ members,having exactly $3$ boys and $2$ girls.
$(ii)$ Let $\alpha_2$ be the total number of ways in which the committee can be formed such that the committee has at least $2$ members,and having an equal number of boys and girls.
$(iii)$ Let $\alpha_3$ be the total number of ways in which the committee can be formed such that the committee has $5$ members,at least $2$ of them being girls.
$(iv)$ Let $\alpha_4$ be the total number of ways in which the committee can be formed such that the committee has $4$ members,having at least $2$ girls and such that both $M_1$ and $G_1$ are $NOT$ in the committee together.
| $LIST-I$ | $LIST-II$ |
| $P$. The value of $\alpha_1$ is | $1. 136$ |
| $Q$. The value of $\alpha_2$ is | $2. 189$ |
| $R$. The value of $\alpha_3$ is | $3. 192$ |
| $S$. The value of $\alpha_4$ is | $4. 200$ |
| $5. 381$ |
| $6. 461$ |
The correct option is: