Let the tan gents drawn to the circle, x^2 + | vedclass

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Question

$OP = \frac{4}{{\sin \,	heta }}$

$OB = \frac{4}{{\cos \,	heta }}$

Area $ = OP 	imes OB = \frac{{16}}{{\sin \,	heta \,\cos \,	heta \,}}

Vedclass · Accepted Answer

$4\sqrt 2$

Vedclass · Answer

$OP = \frac{4}{{\sin \,	heta }}$

$OB = \frac{4}{{\cos \,	heta }}$

Area $ = OP 	imes OB = \frac{{16}}{{\sin \,	heta \,\cos \,	heta \,}} = \frac{{32}}{{\sin \,2	heta }}$

least value $\sin \,2	heta  = 1;	heta  = {45^0}$

So, $h = \frac{4}{{\sin \,{{45}^0}}} = 4\sqrt 2 $

Let the tan gents drawn to the circle, $x^2 + y^2 = 16$ from the point $P(0, h)$ meet the $x-$ axis at point $A$ and $B.$ If the area of $\Delta APB$ is minimum, then $h$ is equal to

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