Let the first term a and the common ratio r o | vedclass

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Question

$\Rightarrow a^2+a^2 r ^2+a^2 r ^4=33033$

$\Rightarrow a^2\left( r ^4+ r ^2+1ight)=3 	imes 7 	imes 11^2 	imes 13 \Rightarrow a=11$

$\Righta

Vedclass · Accepted Answer

$231$

Vedclass · Answer

$\Rightarrow a^2+a^2 r ^2+a^2 r ^4=33033$

$\Rightarrow a^2\left( r ^4+ r ^2+1ight)=3 	imes 7 	imes 11^2 	imes 13 \Rightarrow a=11$

$\Rightarrow r ^4+r^2+1=273 \quad \Rightarrow r^4+r^2-272=0$

$\Rightarrow\left(r^2+17ight)\left(r^2-16ight)=0 \Rightarrow r^2=16 \Rightarrow r = \pm 4$

$t_1+t_2+t_3=a+a r+a r^2=11+44+176=231$

Let the first term $a$ and the common ratio $r$ of a geometric progression be positive integers. If the sum of its squares of first three terms is $33033$, then the sum of these three terms is equal to

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