Let $z = i^{2i}$,then $|z|$ is (where $i = \sqrt{-1}$)

Evaluate: $\frac{\sqrt{6 + 2\sqrt{3} + 2\sqrt{2} + 2\sqrt{6}} - 1}{\sqrt{5 + 2\sqrt{6}}}$

$\sqrt[4]{17 + 12\sqrt{2}} = $

If the real parts of $\sqrt{-5-12 i}$ and $\sqrt{5+12 i}$ are positive,the real part of $\sqrt{-8-6 i}$ is negative,and $a+i b = \frac{\sqrt{-5-12 i}+\sqrt{5+12 i}}{\sqrt{-8-6 i}}$,then $2 a+b =$

The square root of $7+24 i$ is:

$i \log \left( \frac{x - i}{x + i} \right)$ is equal to $(x \in R)$