Let PS be the median of the triangle with ver | vedclass

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(D) The median $PS$ connects vertex $P(2,2)$ to the midpoint $S$ of side $QR$.The coordinates of $S$ are $\left(\frac{6+7}{2}, \frac{-1+3}{2}\right) =

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$2x + 9y + 7 = 0$

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(D) The median $PS$ connects vertex $P(2,2)$ to the midpoint $S$ of side $QR$.The coordinates of $S$ are $\left(\frac{6+7}{2}, \frac{-1+3}{2}\right) = \left(\frac{13}{2}, 1\right)$.The slope of $PS$ is $m = \frac{1-2}{\frac{13}{2}-2} = \frac{-1}{\frac{9}{2}} = -\frac{2}{9}$.Since the required line is parallel to $PS$,its slope is also $m = -\frac{2}{9}$.The equation of the line passing through $(1,-1)$ with slope $m = -\frac{2}{9}$ is given by $y - y_1 = m(x - x_1)$.$y - (-1) = -\frac{2}{9}(x - 1)$$9(y + 1) = -2(x - 1)$$9y + 9 = -2x + 2$$2x + 9y + 7 = 0$.

Let $PS$ be the median of the triangle with vertices $P(2,2)$,$Q(6,-1)$,and $R(7,3)$. The equation of the line passing through $(1,-1)$ and parallel to $PS$ is:

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