Let A(3-i) and B(2+i) be two points in the Ar | vedclass

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(C) Given points are $A(3-i)$ and $B(2+i)$.In the Argand plane,these correspond to coordinates $A(3, -1)$ and $B(2, 1)$.The given equation is $|z-3+i|

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the perpendicular bisector of $AB$

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(C) Given points are $A(3-i)$ and $B(2+i)$.In the Argand plane,these correspond to coordinates $A(3, -1)$ and $B(2, 1)$.The given equation is $|z-3+i|=|z-2-i|$.This can be rewritten as $|z-(3-i)|=|z-(2+i)|$.Let $P$ be the point representing the complex number $z$. Then the equation represents the set of points $P$ such that the distance from $P$ to $A$ is equal to the distance from $P$ to $B$,i.e.,$PA = PB$.The locus of points equidistant from two fixed points $A$ and $B$ is the perpendicular bisector of the line segment $AB$.

Let $A(3-i)$ and $B(2+i)$ be two points in the Argand plane. If the point $P$ represents the complex number $z=x+iy$,which satisfies $|z-3+i|=|z-2-i|$,then the locus of the point $P$ is

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