Let $A$ and $B$ be subsets of a set $X$. Then
$A - B = A \cup B$
$A - B = A \cap B$
$A - B = {A^c} \cap B$
$A - B = A \cap {B^c}$
Let $P=\{\theta: \sin \theta-\cos \theta=\sqrt{2} \cos \theta\}$ and $Q=\{\theta: \sin \theta+\cos \theta=\sqrt{2} \sin \theta\}$ be two sets. Then
If $A$ and $B$ are any two sets, then $A \cap (A \cup B)$ is equal to
$A$ and $B$ are two subsets of set $S$ = $\{1,2,3,4\}$ such that $A\ \cup \ B$ = $S$ , then number of ordered pair of $(A, B)$ is
If $A=\{1,2,3,4\}, B=\{3,4,5,6\}, C=\{5,6,7,8\}$ and $D=\{7,8,9,10\} ;$ find
$B \cup D$
If $A$ and $B$ are two sets such that $A \subset B$, then what is $A \cup B ?$