Let $A$ and $B$ be subsets of a set $X$. Then
$A - B = A \cup B$
$A - B = A \cap B$
$A - B = {A^c} \cap B$
$A - B = A \cap {B^c}$
If $n(A) = 3$ and $n(B) = 6$ and $A \subseteq B$. Then the number of elements in $A \cap B$ is equal to
If $aN = \{ ax:x \in N\} ,$ then the set $3N \cap 7N$ is .....$N$
Show that $A \cap B=A \cap C$ need not imply $B = C$
If $X$ and $Y$ are two sets such that $n( X )=17, n( Y )=23$ and $n( X \cup Y )=38$
find $n( X \cap Y )$
If $A = \{ x:x$ is a natural number $\} ,B = \{ x:x$ is an even natural number $\} $ $C = \{ x:x$ is an odd natural number $\} $ and $D = \{ x:x$ is a prime number $\} ,$ find $A \cap D$