Let S be the set of all ordered pairs (x, y) | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b)

$x$ and $y$ are positive integer

$x^2-y^2=12345678$

$RHS$ $12345678$ is and even number and last digit is $8 .$

$	herefore$ The last

Vedclass · Accepted Answer

$S$ is the empty set

Vedclass · Answer

(b)

$x$ and $y$ are positive integer

$x^2-y^2=12345678$

$RHS$ $12345678$ is and even number and last digit is $8 .$

$	herefore$ The last digit of $x$ be $3,7$

and the last digit of $y$ be $1,9$.

$	herefore x$ and $y$ must be odd and square of difference is multiple of $8$ but $RHS$ is not multiple of $8$ .

$	herefore S$ is the empty set.

Let $S$ be the set of all ordered pairs $(x, y)$ of positive integers satisfying the condition $x^2-y^2=12345678$. Then,

Similar Questions

Let $a>0, a \neq 1$. Then, the set $S$ of all positive real numbers $b$ satisfying $\left(1+a^2\right)\left(1+b^2\right)=4 a b$ is

Consider the two sets : $A=\{m \in R:$ both the roots of $x^{2}-(m+1) x+m+4=0$ are real $\}$ and $B=[-3,5)$ Which of the following is not true?

The number of elements in the set $\left\{ n \in N : 10 \leq n \leq 100\right.$ and $3^{ n }-3$ is a multiple of $7\}$ is $........$.

Let $\bigcup \limits_{i=1}^{50} X_{i}=\bigcup \limits_{i=1}^{n} Y_{i}=T$ where each $X_{i}$ contains $10$ elements and each $Y_{i}$ contains $5$ elements. If each element of the set $T$ is an element of exactly $20$ of sets $X_{i}$ 's and exactly $6$ of sets $Y_{i}$ 's, then $n$ is equal to

Let $S=\{4,6,9\}$ and $T=\{9,10,11, \ldots, 1000\}$. If

$A=\left\{a_{1}+a_{2}+\ldots+a_{k}: k \in N, a_{1}, a_{2}, a_{3}, \ldots, a_{k} \in S\right\}$ then the sum of all the elements in the set $T - A$ is equal to $......$