Let $A=\{x, y, z\}$ and $B=\{1,2\} .$ Find the number of relations from $A$ to $B$.

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It is given that $A=\{x, y, z\}$ and $B=\{1,2\}$

$\therefore A \times B=\{(x, 1),(x, 2),(y, 1),(y, 2),(z, 1),(z, 2)\}$

Since $n(A \times B)=6,$ the number of subsets of $A \times B$ is $2^{6}$

Therefore, the number of relations from $A$ to $B$ is $2^{6}$.

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