Let $A = \{1, 2, 3, 4, 6\}$. Let $R$ be the relation on $A$ defined by $R = \{(a, b) : a, b \in A, b \text{ is exactly divisible by } a\}$. Find the range of $R$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) The relation $R$ is defined as $R = \{(a, b) : a, b \in A, b \text{ is exactly divisible by } a\}$.
We check for each $a \in A$,which $b \in A$ satisfies the condition:
For $a = 1$: $b \in \{1, 2, 3, 4, 6\}$ (since $1$ divides all these numbers).
For $a = 2$: $b \in \{2, 4, 6\}$.
For $a = 3$: $b \in \{3, 6\}$.
For $a = 4$: $b \in \{4\}$.
For $a = 6$: $b \in \{6\}$.
The set of all second elements (the range) is the set of all $b$ values that appear in the ordered pairs of $R$.
Range $= \{1, 2, 3, 4, 6\}$.

Explore More

Similar Questions

The relation $R$ is defined on the set of natural numbers as $\{(a, b) : a = 2b\}$. Then $R^{-1}$ is given by

Show that the relation $R$ defined in the set $A$ of all polygons as $R = \{(P_{1}, P_{2}) : P_{1} \text{ and } P_{2} \text{ have the same number of sides}\}$,is an equivalence relation. What is the set of all elements in $A$ related to the right-angled triangle $T$ with sides $3, 4, \text{ and } 5$?

The number of relations on the set $A = \{1, 2, 3\}$ containing at most $6$ elements including $(1, 2)$,which are reflexive and transitive but not symmetric,is . . . . . . .

Let $N$ denote the set of all natural numbers and $R$ be the relation on $N \times N$ defined by $(a, b) R (c, d)$ if $ad(b + c) = bc(a + d),$ then $R$ is

Difficult
View Solution

Let $R$ be a relation on the set $N$ defined by $\{(x, y) | x, y \in N, 2x + y = 41\}$. Then $R$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo