Let $A$ and $B$ be independent events with $P(A)=0.3$ and $P(B)=0.4$. Find  $P(A \cap B)$

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It is given that $P(A)=0.3$ and $P(B)=0.4$

If $\mathrm{A}$ and $\mathrm{B}$ are independent events, then

$P(A \cap B)=P(A) P(B)=0.3 \times 0.4=0.12$

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