Let z be complex number such that left|frac{z | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\left|\frac{z-i}{z+2 i}\right|=1$

$\Rightarrow|z-i|=|z+2 i|$

$\Rightarrow \quad z$ lies on perpendicular bisector of $(0,1)$ and $(0,-2)$

$\

Vedclass · Accepted Answer

$\frac{7}{2}$

Vedclass · Answer

$\left|\frac{z-i}{z+2 i}ight|=1$

$\Rightarrow|z-i|=|z+2 i|$

$\Rightarrow \quad z$ lies on perpendicular bisector of $(0,1)$ and $(0,-2)$

$\Rightarrow \quad \operatorname{Im} z=-\frac{1}{2}$

Let $z=x-\frac{i}{2}$

$\because \quad|z|=\frac{5}{2} \quad \Rightarrow \quad x^{2}=6$

$	herefore \quad|z+3 i|=\left|x+\frac{5 i}{2}ight|=\sqrt{x^{2}+\frac{25}{4}}$

$=\sqrt{6+\frac{25}{4}}=\frac{7}{2}$

Let $z$ be complex number such that $\left|\frac{z-i}{z+2 i}\right|=1$ and $|z|=\frac{5}{2} \cdot$ Then the value of $|z+3 i|$ is

Similar Questions

If $z_1$ is a point on $z\bar{z} = 1$ and $z_2$ is another point on $(4 -3i)z + (4 + 3i)z -15 = 0$, then $|z_1 -z_2|_{min}$ is (where $ i = \sqrt { - 1}$ )

If $z_1 = 1+2i$ and $z_2 = 3+5i$ , then ${\mathop{\rm Re}\nolimits} \,\left( {\frac{{{{\overline Z }_2}{Z_1}}}{{{Z_2}}}} \right) = $

If ${z_1},{z_2}$ are two complex numbers such that $\left| {\frac{{{z_1} - {z_2}}}{{{z_1} + {z_2}}}} \right| = 1$ and $i{z_1} = k{z_2}$, where $k \in R$, then the angle between ${z_1} - {z_2}$ and ${z_1} + {z_2}$ is

If $z = 3 + 5i,\,\,{\rm{then }}\,{z^3} + \bar z + 198 = $

If $arg\, z < 0$ then $arg\, (-z)\, -arg(z)$ is equal to