Let P = left{ {theta :sin ,theta - cos | vedclass

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Question

$\sin \,	heta \, - \,\cos \,	heta \,\, = \,\,\sqrt 2 \,\cos \,	heta $

$ \Rightarrow \,\sin \,	heta \, = \,\cos \,	heta \,\, + \,\,\sqrt 2 \,\c

Vedclass · Accepted Answer

$P = Q$

Vedclass · Answer

$\sin \,	heta \, - \,\cos \,	heta \,\, = \,\,\sqrt 2 \,\cos \,	heta $

$ \Rightarrow \,\sin \,	heta \, = \,\cos \,	heta \,\, + \,\,\sqrt 2 \,\cos \,	heta $

$ = \,(\sqrt 2 \, + \,1)\cos \,	heta \, = \,\left( {\frac{{2\, - \,1}}{{\sqrt 2 \, - \,1}}} ight)\,\cos \,	heta $

$ \Rightarrow \,(\sqrt 2 \, - \,1)\sin \,	heta  = \,\cos \,	heta $

$ \Rightarrow \,\sin \,	heta \, + \,\cos \,	heta \,\, = \,\,\sqrt 2 \,\cos \,	heta $

$	herefore \,\,P\, = \,Q$

Let $P = \left\{ {\theta :\sin \,\theta - \cos \,\theta = \sqrt 2 \,\cos \,\theta } \right\}$ and $Q = \left\{ {\theta :\sin \,\theta + \cos \,\theta = \sqrt {2\,} \sin \,\theta } \right\}$ be two sets. Then

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