In the figure given below,a block of mass M = | vedclass

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(A) The effective spring constant $K_{	ext{eff}} = K + K$ because both springs are in parallel configuration.$K_{	ext{eff}} = 2K = 2 	imes 2 = 4 \,

Vedclass · Accepted Answer

$20$

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(A) The effective spring constant $K_{	ext{eff}} = K + K$ because both springs are in parallel configuration.$K_{	ext{eff}} = 2K = 2 	imes 2 = 4 \, N \, m^{-1}$.The mass of the block is $M = 490 \, g = 0.49 \, kg$.The time period $T$ of the oscillation is given by $T = 2 \pi \sqrt{\frac{M}{K_{	ext{eff}}}}$.Substituting the values: $T = 2 \pi \sqrt{\frac{0.49}{4}} = 2 \pi \sqrt{\frac{49}{400}} = 2 \pi \left( \frac{7}{20} ight) = \frac{7 \pi}{10} \, s$.The number of complete oscillations $N$ in time $t = 14 \pi \, s$ is $N = \frac{t}{T}$.$N = \frac{14 \pi}{7 \pi / 10} = 14 \pi 	imes \frac{10}{7 \pi} = 20$.

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