In the expansion of {left( {frac{a}{x} + bx} | vedclass

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Question

(c) ${\left[ {\exp \frac{a}{x}} \right]^{12 - r}} + {[\exp bx]^r} = - 10$ 

$ \Rightarrow - 12 + r + r = - 10 $

$\Rightarrow r = 1$

Vedclass · Accepted Answer

$12{a^{11}}b$

Vedclass · Answer

(c) ${\left[ {\exp \frac{a}{x}} \right]^{12 - r}} + {[\exp bx]^r} = - 10$ 

$ \Rightarrow - 12 + r + r = - 10 $

$\Rightarrow r = 1$ 

Then coefficient of ${x^{ - 10}}$ is $^{12}{C_1}{(a)^{11}}{(b)^1} = 12{a^{11}}b$.

In the expansion of ${\left( {\frac{a}{x} + bx} \right)^{12}}$,the coefficient of $x^{-10}$ will be

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