In the given reaction,the end product (C) is: | vedclass

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(B) $1$. The reaction starts with aniline $(C_6H_5NH_2)$.$2$. Treatment with $NaNO_2 + HCl$ at $0-5^{\circ}C$ performs diazotization to form benzene d

Vedclass · Accepted Answer

Benzoic acid

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(B) $1$. The reaction starts with aniline $(C_6H_5NH_2)$.$2$. Treatment with $NaNO_2 + HCl$ at $0-5^{\circ}C$ performs diazotization to form benzene diazonium chloride $(A)$,which is $C_6H_5N_2^+Cl^-$.$3$. Reaction of $A$ with $CuCN/KCN$ (Sandmeyer reaction) replaces the diazonium group with a cyano group to form benzonitrile $(B)$,which is $C_6H_5CN$.$4$. Acidic hydrolysis of benzonitrile $(B)$ with $H_2O/H^+$ converts the cyano group $(-CN)$ into a carboxylic acid group $(-COOH)$,resulting in benzoic acid $(C)$,which is $C_6H_5COOH$.

In the given reaction,the end product $(C)$ is:

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