Benzyl isocyanide can be obtained from which | vedclass

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(A) $1$. Reaction $A$: Benzyl bromide $(C_6H_5CH_2Br)$ reacts with $AgCN$ to form benzyl isocyanide $(C_6H_5CH_2NC)$. This is because $AgCN$ is a cova

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$A$ and $B$ Only

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(A) $1$. Reaction $A$: Benzyl bromide $(C_6H_5CH_2Br)$ reacts with $AgCN$ to form benzyl isocyanide $(C_6H_5CH_2NC)$. This is because $AgCN$ is a covalent compound,and the nucleophilic attack occurs through the nitrogen atom of the ambident $CN^-$ ion.$2$. Reaction $B$: Benzylamine $(C_6H_5CH_2NH_2)$ undergoes the carbylamine reaction with $CHCl_3$ and $KOH$ (or $NaOH$) to form benzyl isocyanide $(C_6H_5CH_2NC)$.$3$. Reaction $C$: Bromobenzene does not undergo nucleophilic substitution with $AgCN$ under normal conditions due to the partial double bond character of the $C-Br$ bond.$4$. Reaction $D$: Aniline $(C_6H_5NH_2)$ undergoes the carbylamine reaction to form phenyl isocyanide $(C_6H_5NC)$,not benzyl isocyanide.$5$. Reaction $E$: $2-$Phenylethyl bromide reacts with $KCN$ to form $3-$phenylpropanenitrile $(C_6H_5CH_2CH_2CN)$.Therefore,benzyl isocyanide is obtained from reactions $A$ and $B$.

List-$I$	List-$II$
$I.$ Benzenesulphonyl Chloride	$A.$ Zwitterion
$II.$ Sulphanilic acid	$B.$ Hinsberg reagent
$III.$ Alkyl Diazonium salts	$C.$ Dyes
$IV.$ Aryl Diazonium salts	$D.$ Conversion to alcohols

Benzyl isocyanide can be obtained from which of the following reactions? Choose the correct answer from the options given below:
$A$. Benzyl bromide + $AgCN$
$B$. Benzylamine + $CHCl_3$ + $Aq. NaOH$
$C$. Bromobenzene + $AgCN$
$D$. Aniline + $CHCl_3$ + $Aq. NaOH$
$E$. $2-$Phenylethyl bromide + $KCN$

Similar Questions

Which among the following represents reagent $A$ in the given reaction?
$C_6H_5N_2^+Cl^- + A \xrightarrow{NaOH} \text{Product (Orange-red dye)}$

Match the compounds given in List-$I$ with the items given in List-$II$.

List-$I$ List-$II$

$I.$ Benzenesulphonyl Chloride $A.$ Zwitterion

$II.$ Sulphanilic acid $B.$ Hinsberg reagent

$III.$ Alkyl Diazonium salts $C.$ Dyes

$IV.$ Aryl Diazonium salts $D.$ Conversion to alcohols

Product $A$ is

Which set of products will be obtained in the following reactions?
$RCN \xrightarrow{\text{reduction}} (a)$
$RCN \xrightarrow[(ii) H_2O]{(i) CH_3MgBr} (b)$
$RNC \xrightarrow{\text{hydrolysis}} (c)$
$RNH_2 \xrightarrow{HNO_2} (d)$

The product $(C)$ of the following reaction is:

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Benzyl isocyanide can be obtained from which of the following reactions? Choose the correct answer from the options given below:$A$. Benzyl bromide + $AgCN$$B$. Benzylamine + $CHCl_3$ + $Aq. NaOH$$C$. Bromobenzene + $AgCN$$D$. Aniline + $CHCl_3$ + $Aq. NaOH$$E$. $2-$Phenylethyl bromide + $KCN$