Consider the following sequence of reactions | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The starting material is $3$-nitrotoluene. $1$. Bromination with $Br_2/Fe$ gives $2$-bromo-$5$-nitrotoluene. $2$. Reduction with $Sn/HCl$ converts

Vedclass · Accepted Answer

$171$

Vedclass · Answer

(C) The starting material is $3$-nitrotoluene. $1$. Bromination with $Br_2/Fe$ gives $2$-bromo-$5$-nitrotoluene. $2$. Reduction with $Sn/HCl$ converts the $-NO_2$ group to $-NH_2$,yielding $5$-amino-$2$-bromotoluene. $3$. Diazotization with $NaNO_2/HCl$ at $273 \ K$ converts the $-NH_2$ group to a diazonium salt,$-N_2^+Cl^-$. $4$. Reduction with $H_3PO_2/H_2O$ removes the diazonium group,resulting in $2$-bromotoluene as the major product $(A)$. The chemical formula of $2$-bromotoluene is $C_7H_7Br$. Molar mass $= (7 	imes 12) + (7 	imes 1) + 80 = 84 + 7 + 80 = 171 \ g \ mol^{-1}$.

Consider the following sequence of reactions to produce major product $(A)$. Molar mass of product $(A)$ is $........... \ g \ mol^{-1}$. (Given molar mass in $g \ mol^{-1}$ of $C : 12, H : 1, O : 16, Br : 80, N : 14, P : 31$)

Similar Questions

Which of the following statements is correct?

The incorrect statement regarding the reaction shown below is:

The relative rate of reaction of the following amines with methyl iodide is:

What does the molecular formula $C_3H_9N$ represent?

The product $(A)$ of the given reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module